Solve by the elimination method
4x-5y=67………………(1)
7y=-25-3x………………(2)
What is the solution of the system?
Solution:-
Multiply equation 1 by 3 and and multiply equation 2 by 4
12x-15y=201………(3)
12x+28y=-100……….(4)
Subtract equation 4 from equation 3
12x-15y-12x-28y=201+100
-43y=301
Y=-7
Put this value in equation 1
4x-5(-7)=67
4x=67-35
X=32/4
X=8