Use factoring to solve the equation. 5m2 – 14m = 0 Solution:- Take m common m(5m-14) = 0 So m = 0 or 5m-14 = 0 m=0 or …
Month: March 2015
Problem 622
Solve the system by the substitution method. 2x+14y=-2………….(1) X=-1-7y…………..(2) Solution:- From equation 1 take 2 common 2(x-7y)=-2 x-7y=-1……………………(3) x+7y=-1……………………(2) add both equation 2x=-2 X=-1 Put this…
Problem 621
Solve by the substitution method x + y= 5………(1) -3x+y= -11………….(2) Solution:- Put the value of y from equations 1 to equation 2 -3x+5-x=-11 -4x=-11-5 4x=16 X=4…
Problem 620
Solve by the elimination method 4x-5y=67………………(1) 7y=-25-3x………………(2) What is the solution of the system? Solution:- Multiply equation 1 by 3 and and multiply equation 2 by…
Problem 619
Solve the system by the elimination method. 2x=4+y…………………(1) -5/4x+y= -1/4………….(2) Solution:- From equation 1 2x-y=4…………(3) Now add equation 2 and equation 3 -5/4x+y+2x-y= -1/4+4 -5/4x+2x=(-1+4*4)/4 3x/4x=15/4 3x=15…
Problem 618
What is the solution of the system? Solve the system of equations by substitution. 5x+y=32……..(1) Y=3x………..(2) Solution:- Put the value of y from equation 2 to equation…
Problem 617
Solve by the elimination method. 2x+2y=-4….(1) -2x+y=13…(2) Solution:- Add equation 1 and 2 2x+2y-2x+y=-4+13 3y=9 Y=9/3 Y=3 Put this value in equation 1 2x+2(3)=-4 2x=-4-6 2x=-10 X=-5
Problem 616
Solve by substitution method. If the system does not have a single ordered pair as a solution, state whether the system is dependent or inconsistent. 6x+42y=30…………………(1) X=5-7y……………………..(2) Solution:-…
problem 615
Find the reciprocal of Solution:- Reciprocal means multiply the given value by other value then answer become 1 So in this question If we multiply it by then…
Problem 614
Evaluate Solution:- When we remove the mod then the value become positive so -(336) Answer:- -336
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