Write the point-slope from of the line’s equation satisfying the given conditions. Then use the point-slope from of the equation to write the slope-intercept from of the equation.

Slope = 6, passing through (2,5)

**Solution:-**

The point-slope from of the equation of a nonvertical line with slope m that passes through the point (x_{1},y_{1}) is y –y_{1} = m (x – x_{1}).

In this problem , m = 6, x_{1} = 2, and y_{1} = 5.

Write the point-slope form of the line satisfying the conditions.

y –y_{1} = m (x – x_{1})

y – 5 = 6(x -2)

The point-slope from of the equation of the line is y – 5 = 6(x -2). Solve this equation for y and write an equivalent equation in slope- intercept form (y = mx +b).

y – 5 = 6 (x-2)

y – 5 = 6x – 12

y = 6x – 7

Therefore, the slope-intercept form of the line’s equation is y = 6x – 7.