Problem 952

A right triangle’s hypotenuse is 14m and one leg is 7\sqrt3m. Find the length of the other leg.




Use the Pythagorean theorem, a2 +b2 = c2.

(7\sqrt{3})^{2}+b^{2}= 14^{2}

Next, simplify (7\sqrt{3})^{2}) and 142.

147 + b2 = 196

Subtract 147 from both sides.

b2  = 49

finally, take the square root of both sides.

b = 7

The other leg has length 7 m.



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