Give the slope and the y-intercept of the line with the given equation. Then, graph the linear equation.
y = 5x + 2
Recall that the slope-intercept from of the equation of a nonvertical line with slope m and y-intercept b is y = mx + b.
Notice that the equation y = 5x + 2 is already in the form y = mx + b.
The slope, m ,is the coefficient of x.
Therefore, the slope of the line whose equation is y = 5x + 2 is equal to 5.
The y-intercept, b, is the constant term. Therefore, the y-intercept of the line whose equation is y = 5x + 2 is equal to 2.
To graph the line, y = 5x + 2, begin by plotting the y-intercept. Plot the point (0,2) on the graph to the right.
Now , obtain a second point using the slope, m. Write m as a fraction, and use rise over run.
The slope is 5. We can write 5 as the fraction .
Therefore, starting at the y-intercept, go up 5units and then to the right 1 unit. Plot this point on the graph to the right.
The line through two points is the graph of the equation.