Evaluate 16log1629
Solution:-
Use the following property of logarithms to evaluate the given if a > 0 and a ≠ 1.
alogax = x (x >0)
Determine the value for a in the given expression.
a = 16
Now determine the value for x in the given expression.
x = 29
alogax = x
16log1629 = 29
Therefore, the value of 16log1629 is 29.