Problem 640

Find S10 for -1 + -7 + -13 + -19 +…

 

Solution:-

 

We know S =

    \[ \frac{n}{2}[2a_{1}+(n-1)d]\]

, Where a1 = first term , n = finding term , d = second term – first term.

S10 =  \frac{10}{2}[2*(-1)+(10-1)(-6)]

S10 = -280

So the value of S10  is  -280

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