Problem 1143

Sir SagarNovember 20, 2015November 23, 20150

Find the eccentricity of the ellipse $\frac{x^{2}}{25}+\frac{(y-7)^{2}}{5}=1$

Solution:-

eccentricity of the ellipse = c/a

c = √(a^2 – b^2)

c = √(25-5)

c= √(20)

c = 2√(5)

eccentricity = (2√5)/5

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