Frustum of a Regular Pyramid

Frustum of a Regular Pyramid

Base and top side lengths: $\left\{\begin{matrix} a_{1},a_{2}, a_{3},.....,a_{n},& \\ b_{1},b_{2}, b_{3},.....,b_{n}& \end{matrix}\right.$

Height: h

Slant height: m

Area of bases: $S_{1},S_{2}$

Lateral surface area: $S_{L}$

Perimeter of bases: $P_{1}, P_{2}$

Scale factor: k

Total surface area: S

Volume: V

1. $S_{L} = \frac{1}{2}(a + c)\sqrt{4h^{2}+b^{2}} + b\sqrt{h^{2}+(a - c)^{2}}$

2. $S_{B}$ = ab

3. S = $S_{B} + S_{L}$

4. V = $\frac{bh}{6}(2a+c)$

One thought on “Frustum of a Regular Pyramid”

andrew says:

December 19, 2018 at 5:02 pm

http://mymathangels.com/tag/frustum-of-a-regular-pyramid/

You use c , but don’t define what c is ?

you define m, but don’t give the equation for m

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