Question-73
Find f (2), f(3), f(4), and f(5) if f is defined recursively by f(0) = -1, f(1) = 2, and for n = 1, 2, …
a) f (n + 1) = f (n) + 4f (n -1).
f (2) = ?
f (3) = ?
f (4) = ?
f (5) = ?
b) f(n + 1) = 
f(n – 1)
f (2) = ?
f (3) = ?
f (4) = ?
f (5) = ?
c) f(n+ 1) = 3 – 5
f(2) = ?
(3) = ?
f(4) = ?
Solution
a)f (2) = -2
f (3) = 6
f (4) = -2
f (5) = 22
b) f (2) = -4
f (3) = 32
f (4) = -4096
f (5) = 536870912
c) f(2) = 7
(3) = 127
f(4) = 48142