Problem 389

Problem 389

The Investment Problem. Suppose that Rod inverts 1,000 at 6% compounded daily Sheila invests1,000 at 7%(per year) simple interest. In how many years will Rod’s investment be worth more than Sheila’s investment? Complete the following table to answer

Your question (the amount for the first 2 years are given; you may not have to do all 10 years):

Year 6% compounded daily 7% simple
1 1,061.83</td> <td valign="top" width="90">1,070.00
2 1,127.49</td> <td valign="top" width="90">1,140.00
3 ? ?
4 ? ?
5 ? ?
6 ? ?
7 ? ?
8 ? ?
9 ? ?
10 ? ?

 

 

Solution

 

Year 6% compound 7% simple
1 1061.83</td> <td valign="top" width="140">1070.00
2 1127.49</td> <td valign="top" width="140">1140.00
3 1197.20</b></td> <td valign="top" width="140"><b>1210.00
4 1271.22</b></td> <td valign="top" width="140"><b>1280.00
5 1349.83</b></td> <td valign="top" width="140"><b>1350.00
6 1433.29</b></td> <td valign="top" width="140"><b>1420.00
7    

 

Now from the table we can see after 6 years Rod’s investment will be worth more than Sheila’s.

 

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