Let U = {16,25,36,49,64,81} and A = {16,25,36} . Find A’.
Solution:-
The complete of A (relative to the universal set U), denoted by A’, is the set of elements in U that are not in A.
A’ = {x ϵ U | x Ɇ A}
Thus, determine all the elements of U that are not in A.
The element 49 of the set U, for instance, is not in set A. Therefore, it is an element of set A’.
However, the element 16 is in both sets A and U. Therefore, 16 is not an element of set A’.
The elements of set A’ are shown below.
A’ = {49, 64, 81}