Problem 1138

A single fair 80 sided die is rolled. Find the probability of getting a 5.

 

Solution:-

 

First, write the sample space S by listing all the possible outcomes for rolling a single die with 8 sides.

S = {1, 2, 3, 4, 5, 6, 7, 8}

The probability of an event E that is a sunset of a sample space S is P(E) = \frac{n(E)}{n(S)}, where n(E) is the number of outcomes in the event and n(S) is the number of outcomes in the sample space.

There are 8 outcomes in the sample space S = {1, 2, 3, 4, 5,6 , 7, 8}, so n(S) = 8.

Only 1 of these outcomes corresponds to getting a 5, so n(E) = 1.

Divide n(E) = 1 by n(S) = 8 to write the probability.

P(E) = \frac{n(E)}{n(S)} = \frac{1}{8}

Therefore, the probability of getting a 5 is \frac{1}{8}.

 

 

 

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