Find a point-slope from the equation of the line satisfying the conditions.

Slope -5 , passing through (2,8)

Solution

The point-slope equation of the line can be in the form y – $y_{1}$ = m(x – $x_{1}$ ) or

y = m(x – $x_{1}$ ) + y1. For this problem, use the form y = m(x – $x_{1}$ ) + y1.

Substitute the given values for $y_{1}$ ,m, and $x_{1}$ into the point-slope equation.

Substitute the y-coordinate of the givrn point for $y_{1}$ .

y = m(x- $x_{1}$ )+8

Substitute the x – coordinate of the point for $x_{1}$ .

y = -5(x – 2) + 8

An equation of the line in point-slope from is the following.

y = -5(x – 2 )+ 8