Algebra

Problem 144

Sir Sagar0

Problem 144

A jar contains four marbles, each a different color: red, blue, green, and yellow. If you draw two marbles from the jar, one after another, replacing the first before drawing the second, what is the probability of getting

 

a. two red marbles?

b. a red marble on the first draw and a green marble on the second draw?

c. at least one red marble and one green marble?

d. no yellow marbles?

 

Solution.

a. P = \frac{1}{4} \ast \frac{1}{4} = \frac{1}{16}

b. P = \frac{1}{4} \ast \frac{1}{4} = \frac{1}{16}

c. P = \frac{1}{4} \ast \frac{1}{4} + \frac{1}{4} \ast \frac{1}{4} = \frac{1}{8}

d. P = 1 – (\frac{1}{4})(\frac{1}{4}) = 1 - \frac{1}{16} = \frac{15}{16}

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