Algebra

Problem 104

Sir Sagar0

Problem 104

In Exercises 9-12, calculate the range, variance, standard deviation, and interquartile range for the data set given.

{72, 80, 80, 82, 88, 90, 96 }

 

Solution

 

Range = 96 – 72 = 24

Mean = \frac{72+80+80+82+88+90+96}{7} = \frac{588}{7} = 84

Variance  \frac{(72-84)^{2}+(80-84)^{2}+(80-84)^{2}+(82-84)^{2}+(88-84)^{2}+(90-84)^{2}+(96-84)^{2}}{7}=\frac{144+16+16+4+16+36+144}{7} = \frac{376}{7}

Variance = 53.71

Standard Deviation = \sqrt{variance}=\sqrt{53.71} = 7.33

Interquartile Q3 – Q1 = 90 – 80 = 10

 

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