Problem 386

Problem  386

Marla earned $400 interest over 2 years on a $4,000 investment.  Jovita earned $960 interest over 4 years on her $6000 investment.  Who had the higher rate of interest?  Explain.

 

Solution

 

Interest for Marla (r) = \frac{400*100}{4000*2}

= \frac{40000}{8000} = 5%

Interest rate for Jovita (r) = \frac{960*100}{6000*4}

= \frac{96000}{24000}

= 3%

Now we can see that Marla has higher interest rate.

 

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