Problem 733

Evaluate 16log1629

 

Solution:-

 

Use the following property of  logarithms to evaluate the given if a > 0 and a ≠ 1.

alogax = x (x >0)

Determine the value for a in the given expression.

a = 16

Now determine the value for x in the given expression.

x = 29

alogax = x

16log1629 = 29

Therefore, the value of 16log1629  is 29.

 

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