Problem 650

The time required to finish a test is normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. What is the z-Score for a student who finishes the test in 45 minutes?

 

Solution:-

 

z = \frac{(45 - 60)}{10}

z =\frac{ -15}{10}

z = -1.5

 

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