Problem 2001

Assume the SAT score are normally distributed with mean 1518 and standard deviation 325. Suppose you randomly select 100 SAT scores and want to find the probability that they have a mean less than 1500. How would you calculate the z score this situation?

 

Solution:-

 

Since you are selecting a group of 100 score, you would use the z-score formula for working with a group

z = \frac{\bar{x-\mu }}{\frac{\sigma }{\sqrt{n}}}

z = \frac{1500-1518}{\frac{325}{\sqrt{100}}}

z = \frac{-36}{65}

 

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