Problem 18

Problem – 18

What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in a drawing if 51 people enter a contest and

a) no one can win more than one prize?

b) winning more than one prize is allowed?

 

Solution :

Probability when no one can win the prize = \frac{1}{51\times50\times49\times48}= \frac{1}{5997600}

Probability when more than one prize is allowed = \frac{1}{51^4}= \frac{1}{6765201}

 

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