Problem 17

Problem – 17

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding67.

 

Solution :

Total ways to selecting the 6 numbers from 67 = C(67,6)

Total ways to selecting the 6 incorrect numbers from (67-6=61) 61 numbers = C(61,6)

So probability = \frac{c(61,6)}{c(67,6)} = 0.56

 

One Response to “Problem 17”

  • Dean says:

    Please do not email me. I only wish to inform you that your solution is written incorrectly. Please flip the numerator and denominator. Solution should be (#ways for success)/(#ways to play).

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