Problem 15

Problem – 15

What is the probability that a five-card poker hand contains the three of hearts, the two of clubs and the jack of diamonds?

 

Solution :

For first three cards (three of hearts, the two of clubs and the jack of diamonds ) we do have choice, so we have to choose remaining 2 cards from the remaining 49 cards. So ways to choose = C(49,2) =1176

And total number of ways to choose five cards = C(52,5) = 2598960

So probability = \frac{1176}{2598960}= \frac{1}{2210}

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